A 1 Kg block is resting on a surface with coefficient of friction μ = 0.1. A force of 0.8 N is applied to the block as shown in the figure. The friction force is
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Given: A 1 Kg block is resting on a surface with coefficient of friction μ = 0.1. A force of 0.8 N is applied to the block as shown in the figure. The friction force is?
To Find: Kg/g_Equation
Engineering Mechanics. Limiting friction force between block and the surface is 0.98 N. But applied force is 0.8 N which is less than the limiting friction force. Therefore friction force for the given case is 0.8 N.
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