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A 1 Kg block is resting on a surface with coefficient of friction μ = 0.1. A force of 0.8 N is applied to the block as shown in the figure. The friction force is​

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Answered by SUNNY90850
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Given: A 1 Kg block is resting on a surface with coefficient of friction μ = 0.1. A force of 0.8 N is applied to the block as shown in the figure. The friction force is?

To Find: Kg/g_Equation

\purple{Answer} Engineering Mechanics. \red{ Solution} Limiting friction force between block and the surface is 0.98 N. But applied force is 0.8 N which is less than the limiting friction force. Therefore friction force for the given case is 0.8 N.

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