Question

a) 1 kg m² s^-2= ....... g cm² s^-2
b) 1m = ....... 1y
c) 3.0 m s^-2 =.......... km h^-2
d) G=6.67 × 10^-11 N m² (kg)^-2 = ...... (cm)³ s^-2 g^-1​

fill in the blanks by suitable conversion of units class 11 chapter units and measurements

Answer 1

Explanation:

Answer:-

(a) 1 kg = 103 g

1 m2 = 104 cm2

1 kg m2 s–2 = 1 kg × 1 m2 × 1 s–2

=103 g × 104 cm2 × 1 s–2 = 107 g cm2 s–2

1 kg m2s–2= 107 g cm2 s–2

(b) Distance = Speed × Time

Speed of light = 3 × 108 m/s

Time = 1 year = 365 days = 365 × 24 hours = 365 × 24 × 60 × 60 sec

Putting these values in above formula we get

1 light year distance = (3 × 108 m/s) × (365 × 24 × 60 × 60 s) = 9.46 × 1015 m

9.46 × 1015 m = 1 ly

So that 1 m = 1/ 9.46 × 1015 ly = 1.06 × 10-16 ly

(c) 1 hour = 3600 sec so that 1 sec = 1/3600 hour

1 km = 1000 m so that 1 m = 1/1000 km

3.0 m s–2 = 3.0 (1/1000 km)( 1/3600 hour)-2 = 3.0 × 10–3 km × ((1/3600)-2 h–2)

= 3.0 × 10–3 km × (3600)2 h–2 = 3.88 × 104 km h–2

3.0 m s–2= 3.88 × 104 km h–2

(d) Given,

G= 6.67 × 10–11 N m2 (kg)–2

We know that

1 N = 1 kg m s–2

1 kg = 103 g

1 m = 100 cm = 102 cm

Putting above values, we get

6.67 × 10–11 N m2 kg–2 = 6.67 × 10–11 × (1 kg m s–2) (1 m2) (1Kg–2)

Solve and cancel out the units we get

⇒ 6.67 × 10–11 × (1 kg–1 × 1 m3 × 1 s–2)

Putting above values to convert Kg to g and m to cm

⇒ 6.67 × 10–11 × (103 g)-1 × (102 cm)3 × (1 s–2)

⇒ 6.67 × 10–11 × 10-3 g-1 × 106 cm3 × (1 s–2)

⇒ 6.67 × 10–8 cm3 s–2 g–1

G= 6.67 × 10–11 N m2 (kg)–2= 6.67 × 10–8 (cm)3s–2 g–1.