Question

A 1 kg mass on a rough horizontal surface is joined to a 2kg mass by a light, inextensible string over a frictionless pulley. Will the 1 kg mass move at a lower, higher or zero acceleration? Explain, based on Newton's laws of motion, and state the law
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Answer 1

Explanation:

Let,

m 1 = 8 kg, m 2 = 5 kg

∵ Pully is frictionless and massless therefore tension force would be same in both side of string. [An idle condition for Law of Motion]

∴ Both masses have same acceleration. Suppose it is a m/s 2 .

Again, consider the direction of motion as 8 kg mass is moving downward and 5 kg mass moving upward or vice-versa.

Lets start to write equations,

For 8 kg mass,

m 1 g - T = m 1 a

8g - T = 8a —————(I)

For 5 kg mass,

T - m 2 g = m 2 a

T - 5g = 5a —————(II)

Adding both equations, we get

8g - 5g = 13a

∴ a = 3g13 m/s 2

Answer 2

Answer:

hope it is helpful for you

Explanation:

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