Question

A 1 kg object is located at a distance of 7.0 * 10 ^ 8 * m from the centre of a larger object whose mass is 2.0*10^ 30 kg . (a) What is the size of the force acting on the smaller object? (b) What is the size of the force acting on the larger object? (c) What is the acceleration of the smaller object when it is released? (d) What is the acceleration of the larger object when it is released?​

Answer 1

(a) let m1=2×10^30 KG

    m2=1 KG

F=Gm1m2/r²

 = ((6.67×10^-11)×(2×10^30)×1) / (7×10^8)²

 =272.244 N

(b)Newton’s Third Law – the forces are equal so the answer is 272.244 N

(c) acceleration of smaller object⇒ F=m2×a2

                      272.244=1KG*a2

                     a2=272.244 m/s²

(d) acceleration of larger object⇒ F=m1×a1

                               272.244=7×10^8×a1

                               a1=38.892×10^-8 m/s²

Answer 2

Answer:

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