a 1 kg stationary bomb exploded in three parts having mass ratio 1:1:3 . parts having same mass moving perpendicular direction with velocity 30mper second then the velocity of bigger part will be
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conservation of momentum
1×0=1 ×30i +1×30j +3v
3v= -(30i +30j)
v = -(10i +10j)
v ( magnitude)= √(10)²+(10)²
=10√2 m/s
may this help you
1×0=1 ×30i +1×30j +3v
3v= -(30i +30j)
v = -(10i +10j)
v ( magnitude)= √(10)²+(10)²
=10√2 m/s
may this help you
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72
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hope this helps you.........
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