A 1 L aqueous solution contain 5 mol of CaCO3 and has density equal to 1.3 g/mL at any particular temperature. If molality of the solution is x. Then the value of 4x is
Answers
Answered by
6
I hope this will be helpful
Attachments:
Answered by
0
Given:
The no of moles of CaCO3, n = 5
The volume of solution, V = 1 L = 1000 mL
The density of solution, d = 1.3 gm/mL
The molality, m = x
To Find:
The value of 4x.
Calculation:
- The mass of solution, W = d × V
⇒ W = 1.3 × 1000 = 1300 gm = 1.3 kg
- Molality = No of moles of solute/Mass of solution
⇒ x = 5/1.3 = 3.846 m
- The value of 4x = 4 × 3.846
⇒ 4x = 15.384
- So, the value of 4x is 15.384
Similar questions