Question

A 1 litre flask contains some mercury . It is found that at different temperatures, the volume of air inside the flask remains the same . What is the volume of mercury in this flask? Given alpha for glass 9 × 10^-6 per degree celsius

Answer 1

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 A one litre glass flask contains some mercury. It is found that at different temperature the volume of air inside the flask remains the same. What is the volume of mercury in this flask if coefficient of linear expansion of glass is while volume expansion of mercury is 1.8 x 10-4 /°C ?

Solution: If V is the volume of flask, VL of mercury and VA of air in it,

V = VL + VA

Now as with change in temperature volume of air remains constant, the expansion of mercury will be equal to that of the whole flask i.e.,

ΔV = ΔVL

VγG Δθ = VLγL Δθ

[ As , ΔV = Vγ Δθ ]

Here V = 1 litre = 1000 cc and γG = 3 α G = 27 x 10-6 / °C

VL = (1000 x 27 x10-6 /1.8 x 10-4 / )= 150 cc.

Answer 2

Answer:

Explanation:

It is said that volume of air remains constant. So expansion of liq=expansion of vessel

1000*3 *9*10^-6=x*1.8*10^-4

150cm^3

Hope this helps