Question

A 1 litre solution of pH = 4 (solution of a strong acid) is added to the 7/3 litre of water. What is the pll of
resulting solution. (log 3 = 0.48)
(A) 4
(B) 4.48
(C)4.52
(D)5​

Answer 1

Answer:

The answers is C 4.52. Hope its helps you

Answer 2

The pH of the resulting solution is 4.52.

Step by step explanation:

From the given,

pH of the solution = 4

pH =4

pH of the solution is indicates concentration of hydrogen ion.

$\bold{[H^{+}]=4}$

$\bold{N_{1}V_{1}=N_{2}V_{2}=10^{-4}}$

solution is added to the 7/3 litre of water.

$10^{4}=N_{2}\times[1+\frac{7}{3}]$

$10^{4}=N_{2}\times \frac{10}{3}$

$N_{2}=3\times 10^{-5}>10^{-6}$

The value is less than $10^{-6}$.

Hence, hydrogen ion concentration of water is not consider.

$[H^{+}]=3\times 10^{-5}$

$pH=5-log(3)$

$pH=5-0.48=4.52$

Therefore, The pH of the resulting solution is 4.52.