Question

A 1 M solution of glucose reaches dissociation
equilibrium according to equation given below
6HCHO = C6H1206. What is the concentration of
HCHO at equilibrium if equilibrium constant is
6x102
[MP PMT 2000]
(a) 1.6x10^
-8 M
(b) 3.2x10^-6M
(c) 3.2x10^-4M
(d) 1.6x10^-4M​

Answer 1

Answer:

The correct option is (d): 1.6x10^-4M​

Explanation:

The dissociation of glucose to form formaldehyde at very high pressure is very low.

Therefore at equilibrium.

Reaction equation is given as below.

6HCHO ----> C6H12O6

Concentration of glucose solution = 1 M

K = [C6H12O6] / 6HCHO

6 x 10^22 = 1/ [HCHO] ^6

[HCHO] = [ 1/6 x 10^22]^1/6

[HCHO] = 1.6x10^-4M​

Thus the concentration of [HCHO] at equilbriul will be 1.6x10^-4M​.