A 1 molal solution of trichlorosacetic acid (CCl₃COOH) is heated to its boiling point. The solution has a boiling point of 100.18°C. Determine the Van’t Hoff factor for CCl₃COOH. ( = 0.512 K kg mol⁻¹)
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10
The answer will be 0.351.
So, trichloroacetic acid shows dissociation.
So, trichloroacetic acid shows dissociation.
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m=1 m
Tb= 100.18°C
T°b= 100°C
i=?
/\ Tb= 0.18°C
/\Tb= kb×i×m
0.18= 0.512K×i×1
0.18/0.512 =i
i= 0.35.
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