(a+1)
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Given:
(A+B)2=A2+B2
⇒(A+B)(A+B)=A2+B2
⇒A(A+B)+B(A+B)=A2+B2
⇒A2+AB+BA+B2=A2+B2
⇒AB+BA=O
So,
[1−12−1][a1b−1]+[a1b−1][1−12−1]=[0000]
⇒[a−b22a−b3]+[a+2−a−1b−2−b+1]=[0000]
⇒[2a−b+2−a+12a−2−b+4]=[0000]
⇒2a−b+2=0,−a+1=0,2a−2=0,−b+4=0
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