a 1 tonne car comes to rest from 20m/s in 4s. what is the break force acted on the car?
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F= m×a
Here m=1000 Kg,v=20 m/s,t=4 s
we know that a=v/t = 20/4 = 5 m/s^2
Therefore we get,
F=1000×5=5000 N
Here m=1000 Kg,v=20 m/s,t=4 s
we know that a=v/t = 20/4 = 5 m/s^2
Therefore we get,
F=1000×5=5000 N
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