(a-1)x²+a²xy+(a+1)y²[factorization]
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Answer:
(ax - x + y)(x + ay + y)
Step-by-step explanation:
(a - 1)x² + a²xy + (a+1)y²
= (a - 1)x² + a²xy - xy + xy + (a+1)y²
= (a - 1)x² + (a² - 1)xy + xy + (a+1)y²
= (a - 1)x² + (a - 1)(a + 1)xy + xy + (a+1)y²
= x(a - 1)[x + (a + 1)y] + y[x + (a + 1)y]
= (ax - x)[x + ay + y] + y[x + ay + y]
= (ax - x + y)(x + ay + y)
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