Math, asked by nanisham2307, 1 month ago

(a-1)x²+a²xy+(a+1)y²[factorization]
step by step​

Answers

Answered by HarshithScamander
1

Answer:

(ax - x + y)(x + ay + y)

Step-by-step explanation:

(a - 1)x² + a²xy + (a+1)y²

= (a - 1)x² + a²xy - xy + xy + (a+1)y²

= (a - 1)x² + (a² - 1)xy + xy + (a+1)y²

= (a - 1)x² + (a - 1)(a + 1)xy + xy + (a+1)y²

= x(a - 1)[x + (a + 1)y] + y[x + (a + 1)y]

= (ax - x)[x + ay + y] + y[x + ay + y]

= (ax - x + y)(x + ay + y)

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