a 10.0 French fry temperature changes by 37 degree Celsius if the final length of the FRI is 50.0 3 cm calculate the coefficient of thermal linear expansion of the fry.
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Answer:
N
2
O
4
(g)⇋2NO
2
(g)
1 mol 0 mol --------------- initially
(1-0.5) mol 2x0.5 mol ----------- at eqbm
Total number of moles =0.5+1=1.5mol
P
N
2
O
4
=
1.5
0.5
×1atm=
3
1
atm
P
NO
2
=
1.5
1
×1atm=
3
2
atm
According to low of chamical equilibrium
K
p
=
P
N
2
O
4
P
NO
2
2
=
(
3
1
)
(
3
2
)
2
=1.33atm
We know
△G
∘
=−2.303RTlogK
p
−−−(1)
Substituting the volume equation (1) we get
△G
∘
=−2.303×(0.082JK
−1
mol
−1
)×(333K)×log(1.33)
=−7.79 atm.lit
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