Question

A 10.0-kg block slides down a smooth inclined plane, which is 10.0m long and inclined at an angle of 30.0 degrees with the horizontal. Find (a) the acceleration of the block, & (b) the velocity at the bottom of the plane.

Use correct formula and please avoid confusing steps (please help)

Answer 1

Hey friend...

Here is your answer.....

K.E = P.E

1/2 m v^2 = mgh

V^2 =2gh

V^2 =2*10*10

B) V=10 root 2 m/s

A) v^2 - U^2 =2ah

U=0

From this :- A=10 m/s^2

HOPE that it will help you....