Question

A 10.10 m long ladder place against a wall. the ladder reached a window 9.9m hight from the ground .find the distance of the foot of the ladder from the wall.​

Answer 1

Answer:

Let AC be the ladder and A be the window.

Given: AC=15m, AB=12m, CB=am

In right angled triangle ACB,

(Hypotenuse)

2

=(Base)

2

+[Perpendicular)

2

[By Pythagoras theorem]

⇒(AC)

2

=(CB)

2

+(AB)

2

⇒(15)

2

=(a)

2

+(12)

2

⇒225=a

2

+144

⇒a

2

=225−144=81

⇒a=

81

=9cm

Thus, the distance of the foot of the ladder from the wall is 9m.

solution

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