Question

A 10 cm tall object is placed perpendicular to a principal axis of a convex lens of focal length 12 CM.
The distance of the object from the lens is 18 cm find the nature position and size of the image formed.

Answer 1

object height =10 cm
f=12 cm
u=-18cm
by using lens formula
1/f =1/v -1/u

36/-18 =-2
10*-2=-20

hi =-20

Answer 2

Hii there,

● Answer -
Position => 36 cm
Size => 20 cm
Nature => maximized, real & inverted image


● Explanation -
# Given -
u = -18 cm
h1 = 10 cm
f = 12 cm

# Solution -
Using lens formula,
1/f = 1/v - 1/u
1/12 = 1/v - 1/-18
1/v = 1/12 - 1/18
v = 36 cm

Magnification by lens is calculated by -
M = -v/u = h2/h1
h2 = -h1 × v / u
h2 = -10 × 36 / (-18)
h2 = 20 cm

Therefore, real & inverted image of size 20 cm is formed 36 cm in front of convex lens.

Hope this helped...