A 10 cm tall object is placed perpendicular to the principal of axis of a convex lens of focal length 12 cm. the distance of the object from the lens is 18 cm. find the nature, position and size of the image formed ?
Answers
Answered by
1
Answer:
Step by Step explanation
Explanation:
using lens formula 1/f=1/v-1/u
1/12=1/v-1/18
1/12+1/18=1/v
18+12/216=1/v
30/216=1/v
0.13=1/v
m=0.13/10
m=1.3
Answered by
1
Answer:
h= 10cm ( height of the image)
u= -18cm (object distance)
f= 12cm
1/v-1/u =1/f
So, 1/v= 1/f+1/u
1/v= 1/12+1/-18=1/36
v=36cm
h'/h = v/u
So,h'= v/u*h
h'= 36/-18*10
h' = -20
Nature: real and inverted because h' is negative
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