Question

A 10 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 30 cm. The distance of the object from the lens is 20 cm. Find the:
(a)Position
(b)Nature​

Answer 1

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Answer 2

Solution

Given

• f = 30 cm
• u = -20 cm

Find :-

• distance of image from focal length (v)
• Nature of image

Explanation

Using Formula

$\dag\boxed{\underline{\tt{\orange{\:\dfrac{1}{f}\:=\:\dfrac{1}{v}-\dfrac{1}{u}}}}}$

Now, keep above Values

==> 1/30 = 1/v - 1/(-20)

==> 1/v = 1/30 -1/20

==> 1/v = (20-30)/600

==> 1/v = -10/600

==> 1/v = -1/60

==> v = - 60 cm

Since,

• Distance of image from focal length be = 60 cm

Nature of image

Here, Distance sign of image is Negative,

That's means it is on same side on lens as the object and it is a real image.

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