Question

a 10 cm tall object is placed perpendicular to the principal axis of a concave mirror of focal length 12 cm. the distance of the object from the mirror is 18 cm. find the nature, position and size of the image formed.

Answer 1

Answer:

Explanation:

Given : height of the object =10 cm

focal length = -12 cm [minus came using of sign conventions]

u=-18 cm

1/v= 1/f- 1/u

1/v = 1/-12 - 1/-18

= -3-2/36

1/36

h= -v/u

10= -36/18 =20 cm

v=36 cm

m= -v/u

-36/18 =20 cm

real and inverted and diminished image