Question

A 10 g bullet is fired with a velocity of 300 m/s into a pendulum bob of mass 990 g. How high

does the pendulum bob (plus bullet) swing after the collision? ​

Answer 1

Here, a bullet weighing 10 g and moving at 300 ms

−1

strikes a 5 kg block of ice and drops dead hence

m

1

u

1

+m

2

u

2

=m

2

v

10×10

−3

(300)+(5)(0)=5v

3000×10

−3

=5v

v=

5

3

=0.6ms

−1