Question

A 10 g bullet is shot from a 5 kg gun with a velocity of 400m/s. What is the speed of
the recoil of the gun?​

Answer 1

Explanation:

v=-0.8m/s

Negative sign shows that the gun moves in a direction opposite to that of the bullet.

Answer 2

Answer:

Explanation:

If a 10g bullet is shot from a 5kg gun with a velocity of 400m/sec, what is the recoil velocity of the gun?

This problem can be solved using conservation of momentum.

As before firing the bullet both the gun and the bullet were at rest, so the total momentum before firing is zero

after firing the velocity of bullet (v)= 400 m/s, say the velocity of gun is V

mass of bullet (m)= 10/1000 kg , mass of gun (M)= 5 kg

From momentum conservation,

0= mv + MV

V = - (m/M)*v

V = - (10\5000)*400 m/s

V = - 0.8 m/s (Negative sign indicates that velocity of gun and bullet is in opposite direction)

so the recoil velocity of the gun is 0.8 m/s