Question

A 10 g bullet, moving with a velocity of 500 m/s.
enters a stationary piece of ice of mass 10 kg
and stops. If the piece of ice is lying on a
frictionless plane, then its velocity will be
(1) 5 cm/s
(2) 5 m/s
(3) 0-5 m/s
(4) 0-5 cm/s​

Answer 1

$\huge{\underline{\underline{.........Answer.........}}}$

$\huge{\underline{Given:-}}$

Let the mass of bullet be ${ m_1 = 0.01 kg = 10 grams}$

and mass of ice be ${m_2 = 10 kg}$

Let the initial velocity of bullet be ${u_1 = 500 m/s}$

and initial velocity of bullet be ${u_2 = 0 m/s}$

Let the final velocity of bullet be ${v_1 = 0 m/s}$

and final velocity of bullet be ${v_2 = x m/s}$

$\huge{\underline{Explanation:-}}$

From the law of conservation of momentum.

$\huge{\boxed{\boxed{m_1u_1 + m_2u_2 = m_1v_1 + m_2u_2}}}$

Substituting the values.

${0.01 \times 500 + 0 = 0 + 10x}$

${10x = 5 }$

${x = \frac{1}{2}}$

${x = 0.5 m/s}$

$\huge{\boxed{\boxed{v_2 = 0.5 m/s}}}$

$\huge{\boxed{\boxed{Option--3}}}$

So,ice will move with a velocity of 0.5 m/s

Answer 2

Answer:

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