A 10 g bullet with a horizontal velocity of 300 m.s-1
hits a wooden block of mass 290 g. After collision, the
block and the bullet move together and come to rest
after travelling 15 m horizontally. What is the coeffi-
cient of friction between the block and the horizontal
plane on which it is kept?
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Explanation:
v²=u²-2as
0= 9×10⁴-30a
a= 3× 10³ m/s²
F = ma
= 3×10³×1/100
= 30N (force of bullet on block)
F = kmg (force of friction is equals force by bullet)
30= k×0.29×10
k= 10.1
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