A 10 g mixture of H2CO3 and H2C2O4 requires 400ml 0.1M KMnO4. The percentage composition of H2C2O4 in the mixture is?
Answers
Answer:
Assume that a mixture of Na
2
C
2
O
4
and KHC
2
O
4
.H
2
C
2
O
4
required 1 L of 0.2 M KMnO
4
and 1 L of 0.2 M NaOH separately for complete titration.
1 L of 0.2 M NaOH corresponds to 1L×0.2mol/L=0.2 moles of NaOH.
1 mole of KHC
2
O
4
.H
2
C
2
O
4
will react with 3 moles of NaOH.
So 0.2 moles of NaOH will react with
3
0.2
=0.0667 moles of KHC
2
O
4
.H
2
C
2
O
4
.
1 L of 0.2 M KMnO
4
corresponds to 1L×0.2mol/L=0.2 moles of KMnO
4
5 moles of Na
2
C
2
O
4
will react with 2 moles of KMnO
4
.
0.2 moles of KMnO
4
will react with
2
5
×0.2=0.5 moles of Na
2
C
2
O
4
The mole ratio Na
2
C
2
O
4
: KHC
2
O
4
H
˙
2
C
2
O
4
= 0.5:0.0667=
2
15
Explanation: