Question

A 10 g moving body is acted upon by a force of 10 N for 3 micro second . Compute the impulse and the change
in velocity of the body.
​

Answer 1

Explanation:

Impulse=F.t = 10N× 3×10^-6s

3× 10^-5Ns

Impulse is nothing but change in momentum

F.t= M(Vf - Vi )

Vf- Vi= F.t/M

∆V = 3×10^-5/ 0.01

= 3×10^-5× 10^+2

3× 10^-3m/s

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Answer 2

The impulse and the change  in velocity of the body is $J=3\times 10^{-5}\ N-s$ and $(v-u)=0.003\ m/s$.

Explanation:

Given that,

Mass of the body, m = 10 g = 0.01 kg

Force, F = 10 N

Time, $t=3\ \mu s=3\times 10^{-6}\ s$

We need to find the impulse and the change  in velocity of the body. We know that the impulse delivered by an object is given by the product of force and time such that,

$J=F\times t$

$J=10\ N\times 3\times 10^{-6}\ s$

$J=3\times 10^{-5}\ N-s$

So, the impulse delivered by an object is $J=3\times 10^{-5}\ N-s$.

Impulse delivered by an object is given by the change in its momentum such that,

$J=m(v-u)$

$(v-u)=\dfrac{J}{m}$

$(v-u)=\dfrac{3\times 10^{-5}}{0.01}$

$(v-u)=0.003\ m/s$

Therefore, the impulse and the change  in velocity of the body is $J=3\times 10^{-5}\ N-s$ and $(v-u)=0.003\ m/s$.

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