A 10 gram bullet travelling at 200 m/sec strikes and remains embedded in a 2 kg target which is originally at rest but free to move .at what speed does the target move off
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m¹=10gm,m²=2kg, u¹=200m/sec,u²=0
we have to find v...
m¹u¹+m²u²=v(m¹+m²)
0.01×200+2×0=v(0.01+2)
note I have converted 10gm into kg ...
now you calculate and find your ans
we have to find v...
m¹u¹+m²u²=v(m¹+m²)
0.01×200+2×0=v(0.01+2)
note I have converted 10gm into kg ...
now you calculate and find your ans
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