Question

a 10 gram bullet travelling at 200 square strikes the remain embedded in a to kilogram target which is organised at rest but free to move at what speed of target move off ?
numerical solution

Answer 1

Answer:

Mass of bullet, m1 = 10g = 0.01 kg Velocity of bullet v1 = 200 m/s Mass of block with the bullet as bullet gets embedded in it, m2 = 2+0.01 = 2.01 kg Recoil velocity v2 According to the law of conservation of momentum m1 x v1 = m2 x v2 0.01 x 200 = 2.01 x v2 Read more on Sarthaks.com - https://www.sarthaks.com/120480/bullet-travelling-strikes-and-remains-embedded-target-which-originally-rest-but-free-move?show=120487#a120487