A
10. In the given figure, D is the mid-point of BC and E is any
point on AD. Prove that :
(i) ar (AEBD) = ar (AEDC).
E
(ii) ar (AABE) = ar (AACE).
B
Answers
Answered by
3
Answer:
but where is the figure
please attach it!
Answered by
3
Answer:
In △ABC
D is mid point of BC
⇒AD is the median.
similarly In △EBC
D is mid point of BC
⇒ED is median.
As median divides a given triangle
in two triangles of equal area
⇒ar(△ABD)=ar(△ACD) ___(1)
ar(△EBD)=ar(△ECD) __(2)
(1)-(2) statement
ar(△ABD)−ar(△EBD)=ar(△ACD)−ar(△ECD)
⇒ar(△ABE)=ar(△ACE)__(3)
statement (2) and (3) are proof of
part (I) and (II) respectively.
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