A 10 kg ball is dropped from a height of 5m. Then the kinetic energy just before it reaches the ground (g=10m/s)
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Mass of ball , m = 10 kg
Height from where the ball was dropped ,h = 5m/s
Initial velocity of ball ,u = 0 m/s
Acceleration ,g = 10 m/s sq.
Kinetic enery of the ball , k.E = ?
Final velocity , v = ?
So, v sq. - u sq. = 2gh
V sq. - 0 sq. = 2 × 10 × 5
V sq. = 100
V = 10
K.E = 1/2 m v sq.
= 1/2 × 10 × 10 ×10
= 500 J
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