Question

A 10 kg ball is thrown into the air. It is going 3.0 m/s when thrown. How much potential energy will it have at the top? (ignoring air resistance)

Answer 1

Answer:

45 J

Explanation:

Initial Velocity, u = 3 m/s

Acceleration, g = -10 m/s^2

Final Velocity, v = 0 m/s

v^2 - u^2 = 2gh

0 - 9 = -20h

h = 9/20 m

Height = 9/20 m

Now,

Potential Energy = mgh = 10 × 10 × 9/20 J = 45 J

Answer 2

Answer:

= 4 5 J

Explanation:

Given : A 1 0 kg ball is thrown into the air. It is going 3 . 0 m / s when thrown .

To find : How much potential energy will it have at the top ?

Solution :

Initial Velocity , u = 3 m / s

Acceleration , g = - 1 0 m / s ^ 2

Final Velocity , v = 0 m / s

v ^ 2 - u ^ 2 = 2 0 h

0  - 9 = - 2 0 h

h = 9 / 2 0 m

Height = 9 / 2 0 m

Now ,

Potential Energy

= m g h = 1 0 × 1 0 × 9 / 2 0 J

= 4 5 J

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