Question

a 10 kg ball is thrown upwards with a speed of 5 m/s. (a) find its potential energy when it reaches the highest point (b) close calculate the maximum height it reaches.​

Answer 1

Answer:

(i)125J (ii)1.25 metres

Explanation:

according law if conservation of energy kinetic energy at ground level = potential energy at highest level

so

$mgh = m {v}^{2} \frac{1}{2}$

/2

so 5×5×10\2=125 joules

for(b) use

${v}^{2} - {u}^{2} = 2as$

so 0-25 =2 ×-10×s ( considering downward direction to be negative)

then s= 1.25 metres