Question

A 10 kg ball is thrown upwards with a speed of 5m/s. (a) find its potential energy when it reaches the highest point. (b) calculate the maximum height it reaches. ​

Answer 1

Explanation:

Data

M=10kg

V=5m/s

g=10m/s^2

h=?

Formula

PE=mgh

KE=1/2mv^2

Calculation

C) KE=1/2*10*5^2=125J

a) KE=PE

PE=125J

b)h=PE/mg

h=125/100

h=1.25m

d)h=1.25/2=0.625

PE=10*10*0.625

PE=62.5J

PE=KE=62.5J

Answer 2

Answer:- given:-

mass = 10kg , v = s

P.E = K.E

K.E = 1/2 mv²

K.E = 1/2×10×(5)²

K.E = 1/2×10×25

K.E = 125J

K.E =mgh

125j= 10×9.8×h

h = 125/10×9.8

h = 1.28 m

I hope this answer is helpful for you thanks