Question

A 10 kg ball is thrown upwards with a velocity of 5 m/s. calculate (a)P.E. when it reaches the highest point.
(b) maximum height it reaches take g=10m/s2
(c) initial K.E.
(d) K.E. and P.E. when it reaches half of the maximum height.

Answer 1

Data
M=10kg
V=5m/s
g=10m/s^2
h=?
Formula
PE=mgh
KE=1/2mv^2
Calculation
C) KE=1/2*10*5^2=125J
a) KE=PE
PE=125J
b)h=PE/mg
h=125/100
h=1.25m
d)h=1.25/2=0.625
PE=10*10*0.625
PE=62.5J
PE=KE=62.5J

Answer 2

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