Question

A 10 kg body hangs at rest from a rope wrapped arounda cylinder 02 m in diameter. The torque applied aboutthe horizontal axis of the cylinder is(1) 98 N-m(2) 19.6 N-m(3) 196 N-m(4) 9.8 N-m​

Answer 1

The torque applied about the horizontal axis of the cylinder is 9.8 N-m.

Explanation:

Given data:

Mass of the body "m"  = 10 Kg

Diameter od cylinder "d" = 0.2 m

Radius "r" =0.1 m

Using torque formula:

τ = rFsinθ     (Since θ = 90°)

Now F = mg = 10 x 9.8 = 98 N

τ = 0.1 x 98 = 9.8 N-m

Thus The torque applied about the horizontal axis of the cylinder is 9.8 N-m.

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