Question

a 10 kg body is dropped from a height of 20 m. What is its potential energy before dropping? what is its kinetic energy when it is 8.0 m high above the ground? what when it hits the ground? (g = 9.8m s^-2).

Answer 1

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Here's your answer...

m = 10 kg
g = 9.8 m/s²
mg = 98 N

20 m above ground, potential energy = mgh
= 98×20 = 1960 J

This is a conservative field, so energy is conserved.

PE(initial) + KE(initial) = PE(final) + KE(final)
1960 + 0 = 98×8 + KE
KE = 1960-784
= 1176 J

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Answer 2

Answer is in picture.

I hope it helps you