Question

A 10 kg heavy block is displaced unto 5m, at constant speed. What will be the force
of friction if work done against the friction is 98 J.
(a) 9.8 N
(b) 98N
(c) 196 N
(d)19.6N
(correct answer is d why?)​

Answer 1

$\blue{\boxed{\huge{\red{\boxed {\green{\mathfrak{ANSWER}}}}}}}$

$\orange{\underline{\huge</p><p>{\bold{\textit{\green{\bf{19.6\: N}}}}}}}$

Reason :-

$energy(joule) = force(newton) \times distance(meter)$

28J = (force)5 m

$\frac{28}{5} = force$

19.6 N = Force.

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