Question

a 10 kg iron bar specific heat capacity of 0.1 calories per gram degree Celsius at 80 degree celsius is placed on block of ice how much ice melts

Answer 1

The specific heat capacity of iron = 0.1 Cal/g°C
The melting point of ice = 0°C.
Hence, Change in Temperature = 80°C - 0°C =80°C
Mass of the iron bar = 10 kg =10,000g
Therefore, quantity of heat lost (q)
= mct
= 10000 * 0.1 * 80
= 80,000 Calories