A 10 kg iron plate contains 2000j potential energy at a height.Find out its height
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300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. The work done against friction is (Take g = 10m/s
2
)
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Correct option is
B
100 J
Given,
Work done =300J, mass=2kg,height=10m,g=10m/s
2
we know that the work done =fd
300=(mgsinθ+f)×
sinθ
h
Work-done against the friction:
f.
sinθ
h
=300−mgsinθ×
sinθ
h
⇒300−mgh=300−2×10×10=100J
Answer:
The height of the iron plate is 20.41 m.
Explanation:
Potential energy is the energy possessed by an object due to its position or configuration. If 'm' is the mass of the object and it is placed at a height 'h' above the horizontal surface, then the potential energy, 'P' of the object is given by the equation:
P = mgh
Where g is the acceleration due to gravity.
We have P = 2000 J and m = 10 Kg
From the above equation height can be calculated as:
h = P /mg
= 2000 / (10 × 9.8)
∴ h = 20.41 m