a 10 kg mass is placed at a tower of height 50m thn it fall dwn with a velocity 15m/s...find kinetic energy 'd pe of the body
Answers
Answered by
1
m =1 0 kg
height h = 50 m
It travels with an initial velocity of 15 m/sec. u = 15 m/s
its initial potential energy = m g h = 10 kg * 9.81 m/sec² * 50 m
= 4, 905 Joules
Initial kinetic energy = 1/2 m v² = 1/2 * 10 kg * 15m/s)² = 1, 125 Joules
Initial total energy = 4 905 + 1125 = 6, 030 JOules
The total energy remains constant. When the body touches the ground, the potential energy is converted into the kinetic energy.
so PE = 0, and KE = 6, 030 joules.
height h = 50 m
It travels with an initial velocity of 15 m/sec. u = 15 m/s
its initial potential energy = m g h = 10 kg * 9.81 m/sec² * 50 m
= 4, 905 Joules
Initial kinetic energy = 1/2 m v² = 1/2 * 10 kg * 15m/s)² = 1, 125 Joules
Initial total energy = 4 905 + 1125 = 6, 030 JOules
The total energy remains constant. When the body touches the ground, the potential energy is converted into the kinetic energy.
so PE = 0, and KE = 6, 030 joules.
Similar questions