Question

A 10 kg object is at rest. A son force is applied. What is the velocity after 4 secs

Please someone help me with this one.

Answer 1

Answer:

-3m/s

Explanation:

Solution

Solutionverified

SolutionverifiedVerified by Toppr

SolutionverifiedVerified by TopprCorrect option is

SolutionverifiedVerified by TopprCorrect option isC

SolutionverifiedVerified by TopprCorrect option isC−3m/s

SolutionverifiedVerified by TopprCorrect option isC−3m/s 2

SolutionverifiedVerified by TopprCorrect option isC−3m/s 2

SolutionverifiedVerified by TopprCorrect option isC−3m/s 2 Change in velocity

SolutionverifiedVerified by TopprCorrect option isC−3m/s 2 Change in velocity −2−10=−12

SolutionverifiedVerified by TopprCorrect option isC−3m/s 2 Change in velocity −2−10=−12Time required is 4 seconds

SolutionverifiedVerified by TopprCorrect option isC−3m/s 2 Change in velocity −2−10=−12Time required is 4 seconds a=Δv/t

SolutionverifiedVerified by TopprCorrect option isC−3m/s 2 Change in velocity −2−10=−12Time required is 4 seconds a=Δv/t=−12/4

SolutionverifiedVerified by TopprCorrect option isC−3m/s 2 Change in velocity −2−10=−12Time required is 4 seconds a=Δv/t=−12/4=−3m/s²

SolutionverifiedVerified by TopprCorrect option isC−3m/s 2 Change in velocity −2−10=−12Time required is 4 seconds a=Δv/t=−12/4=−3m/s²Hence,

SolutionverifiedVerified by TopprCorrect option isC−3m/s 2 Change in velocity −2−10=−12Time required is 4 seconds a=Δv/t=−12/4=−3m/s²Hence,option C is correct answer.

Answer 2

Answer:

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