Question

A 10 kg rubber block sliding on a concrete floor (µ=0.65).
Find its kinetic friction.

Answer 1

Answer:

A 10 kg rubber block sliding on a concrete floor (µ=0.65).

fk= µk Fn

fk=O.65 .(10kg. 9.8m/s²)

fk= 637N

Answer 2

Answer:

63.7≈65N

Explanation:

Given;

mass=10kg

coefficient of friction=0.65

To find:

Friction

Solution

f=coefficient ×normal

w.k.t normal =mg = 9.8×10=98N

.

. .

• f =0.65×98=63.70N

≈65N(when g is taken as 10m/s²)