A 10 kg small block is pulled in the vertical plane along a frictionless surfac
in the form of an arc of a circle of radius 10 m. The applied force is of 200
as shown in the figure. If the block started from rest at A, the speed at
would be: (g = 10 m/s2)
(A) V3 m/s
(B) 10/3 m/s
(C) 100/3 m/s
(D) None of these
Answers
Answer:
The correct answer will be option D. As the answer is 10√3 m/s
Explanation:
According to the problem the mass of the block is 10 kg which is pulled in a vertical plane wit a force along an arc.
According to the figure the initial position of the block is A and we re applying F force to pull it to B
The block is moving as the force is passing energy to the block which is equal to its work done
W = force x displacement
Now displacement means the shortest path. Now from <ACB = 60°
As the two arm has the same length of R
Therefore <CAB= 60°
Therefore the displacement will be R
Therefore the work done at point A
W = 200 x 10 = 2000 Joule
Now it is the kinetic energy
Then,
2000 = 1/2 mv^2 + (mg(R-Rcos60°)
=> 2000 = 1/2 10 x v^2 + (10 x 10 (10(1-1/2)))
=> v = 10√3 m/s
Answer:
Explanation:
Here force direction varies with displacement right?