Physics, asked by vinaykrishna3336, 1 year ago

A 10 kg wagon is pushed with a force of 7 newton for 1.5 seconds then with a force of 5 newton for 1.7 seconds and then with a force of 10 newton for 3 seconds in the same direction what is the change in velocity brought about???

Answers

Answered by JemdetNasr
9

m = mass of wagon = 10 kg

F = force applied = 7 N

t = time duration = 1.5 s

v₁ = initial velocity

v₂ = final velocity

using impulse -change in momentum equation

m (v₂ - v₁ ) = F t

10 (v₂ - v₁ ) = 7 x 1.5

v₂ - v₁ = 1.05 m/s

v₂ = v₁ + 1.05 eq-1


m = mass of wagon = 10 kg

F = force applied = 5 N

t = time duration = 1.7 s

v₂ = initial velocity

v₃ = final velocity

using impulse -change in momentum equation

m (v₃ - v₂ ) = F t

10 (v₃ - v₂ ) = 5 x 1.7

v₃ - v₂ = 0.85 m/s

v₃ - v₁ - 1.05 = 0.85

v₃ - v₁ = 1.9

v₃ = v₁ + 1.9 eq-2



m = mass of wagon = 10 kg

F = force applied = 10 N

t = time duration = 3 s

v₃ = initial velocity

v₄ = final velocity

using impulse -change in momentum equation

m (v₄ - v₃ ) = F t

10 (v₄ - (v₁ + 1.9) ) = 10 x 3

v₄ - v₁ - 1.9 = 3 m/s

v₄ - v₁ = 4.9

so change in velocity is 4.9 m/s





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