Question

A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass-spring system is disturbed from its rest state by the force f(t) = 40 cos(8t). The force f(t) is expressed in newtons and is positive in the downward direction, and time is measured in seconds. Determine the spring

Answer 1

The spring is a spring

Answer 2

The spring constant is 1000 N/m.

Explanation:

Given that,

Stretched spring = 9.8 cm

Mass of object = 10 kg

We need to calculate the spring constant

Using restoring force

$F=kx$

$mg = kx$

$k=\dfrac{mg}{x}$

Put the value into the formula

$k=\dfrac{10\times9.8}{9.8\times10^{-2}}$

$k=1000\ N/m$

Hence, The spring constant is 1000 N/m.

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Topic : spring constant

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