Question

A 10 m 50 cm high vertical pole casts a shadow 6 m long. Find at the same time the length of the shadow cast by another pole 5 m 60 cm high.​

Answer 1

Answer: let the shadow casted be x metre.

10m50cm=1050cm

6m=600cm

5m60cm=560cm

1050/600=560/x

x=600 x 560/1050

x=320cm= 3m 20cm

Step-by-step explanation:

Answer 2

Answer:

The length of the shadow casted by pole of length 5m 60 cm is 32m

Step-by-step explanation:

Let us diagrammatically represent the given data.

In Δ ABC,

Let ∠ ACB = y

We know that tan x = $\frac{Perpendicular}{Base}$

                       tan x = $\frac{10.50}{60}$              --(i)

Similarly, in Δ DEC,

As ∠ DCB  = ∠ ACB = y                  (the time is same => angle is the same)

We know that tan x = $\frac{Perpendicular}{Base}$

                       tan x = $\frac{5.60}{x}$                    --(ii)

On equating equation (i) and (ii),

we get,

$\frac{10.50}{60}$   =   $\frac{5.60}{x}$  

=> x(10.50) = 5.60 * 60

=> x = 32

Therefore, the length of the shadow casted by pole of length 5m 60 cm is 32m