A 10 m high rocket containing liquid ful of specific gravity 1.2 lifts off at an acceleration of 5 g . The pressure ob the bottom plate of the rocket at luft off is
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i think its ans is 1.2×10×6g=72g
here g=10m/s^2 so ans is 720 N/m
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Answer:
7.2 kg/cm^2
Explanation:
the height of fuel column (h) = 10 m
pressure at bottom p = ९fuel ( a+g )h
a is upward acceleration
rho fuel = sp. gravity * rho w
= 1.2 * 1000
= 1200 kg/m^3
p= 1200 * (5g+g)*10
= 1200 * 6 * 10 * 100
=7.2 * 10^5 N/m^2
= 7.2 kg/cm^2
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