Question

A 10 m ladder is placed in such a way that its foot is at a distance of 6m from a wall and its top reaches a window. The height of the window above the ground is (a) 15 m (b) 20 m ) (d) so mo​

Answer 1

Answer:

Let say Wall height =AC=8 m and Distance of ladder's foot from the wall =BC=6 m

Using the Pythagoras theorem, we get

(AB)

2

=(AC)

2

+(BC)

2

⇒(AB)

2

=(8)

2

+(6)

2

⇒(AB)

2

=64+36

⇒(AB)

2

=100

⇒(AB)=

100

⇒AB=10

∴ Length of the ladder =10 m

Answer 2

Answer:

Apply Pythagoras theorem

10^2=6^2+ height^2

height^2=10^2-6^2=64=8^2

h=8mAns