A 10 m long iron chain of linear mass density 0.8 kg m–1 is
hanging freely from a rigid support. If g = 10 ms⁻², then the
power required to left the chain upto the point of support in
10 second
(a) 10 W (b) 20W
(c) 30 W (d) 40 W
Answers
Answer:
(b) 20W
Explanation:
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Question:-
A 10 m long iron chain of linear mass density 0.8 kg m–1 is
hanging freely from a rigid support. If g = 10 ms⁻², then the
power required to left the chain upto the point of support in
10 second
(a) 10 W (b) 20W
(c) 30 W (d) 40 W
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first of all find centre of gravity of chain.
here centre of gravity lies at the centre of length of chain . e.g., C.O.G = h = 10m/2 = 5m
given, mass density = 0.4 kg/m
length of chain , l = 20m
so, mass of chain = l × mass density
= 20 × 0.4 = 8 kg
so, potential energy of chain = mgh
= 8 × 10 × 5 = 400J
power = energy/time,
so, power = 400/2 = 200W
hence, power required to lift the chain upto the point of support in 2 s is 200W
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