A 10 metre long rope is to be cut into 2 pieces and a square is to be made using 3 each. The difference in the area enclosed must be 1 1/ 4 square metres. How should it be cut,?
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A 10 metre long rope is to be cut into two pieces and a square is to be made using each. The difference in the areas enclosed must be 1 1/4 square metres. How should it be cut?
According to question
x + y = 10 --------------(1)
Area of larger square – area of smaller square = 1 1/4 = 5/4
So x^2 – y^2 = 5/4
(x + y)(x – y) = 5/4
10(x – y) = 5/4
(x – y) = 1/8
So 8x – 8y = 1------------(2)
From 1 and 2 we get
x + y = 10 multiply by 8
8x – 8y = 1
So we get
8x + 8y = 80
8x – 8y = 1
16 x = 81
x = 81/16
putting x = 81/16 in 2 we get
8(81/16) - 8y = 1
81/2 - 8y = 1
81/2 = 1 + 8y
81/2 – 1 = 8y
8y = 79/2
y = 79/2 x 1/8
y = 79/16
Therefore the length of the rope after cutting will be 81/16 and 79/16
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